这篇文章主要介绍了python比较2个xml内容的方法,涉及Python操作XML文件的相关技巧,需要的朋友可以参考下
本文实例讲述了python比较2个xml内容的方法。分享给大家供大家参考。具体分析如下：
from xml.etree import ElementTree
OK=True
main_pid = 10000
loop_depth = 0
def compare_xml(left, right, key_info='.'):
global loop_depth
loop_depth += 1
if loop_depth == 1: print
if left.tag != right.tag:
print_diff(main_pid, key_info, 'difftag', left.tag, right.tag)
return
if left.text != right.text:
print_diff(main_pid, key_info, 'difftext', left.text, right.text)
return
leftitems = dict(left.items())
rightitems = dict(right.items())
for k,v in leftitems.items():
if k not in rightitems:
s = '%s/%s' % (key_info, left.tag)
print_diff(main_pid, s, 'lostattr', k, "")
for k,v in rightitems.items():
if k not in leftitems:
s = '%s/%s' % (key_info, right.tag)
print_diff(main_pid, s, 'extraattr', "", k)
leftnodes = left.getchildren()
rightnodes = right.getchildren()
leftlen = len(leftnodes)
rightlen = len(rightnodes)
if leftlen != rightlen:
s = '%s/%s' % (key_info, right.tag)
print_diff(main_pid, s, 'difflen', leftlen, rightlen)
return
l = leftlen<rightlen and leftlen or rightlen
d = {}
for i in xrange(l):
node=leftnodes[i]
if node.tag not in d:
d[node.tag] = 1
tag = node.tag
else:
tag = node.tag + str(d[node.tag])
d[node.tag] += 1
s = '%s/%s' % (key_info, tag)
compare_xml(leftnodes[i], rightnodes[i], s)
def print_diff(main_pid, key_info, msg, base_type, test_type):
global OK
info = u'[ %-5s ] %s -> %-40s [ %s != %s ]'%(msg.upper(), main_pid, key_info.strip('./'), base_type, test_type)
print info.encode('gbk')
OK = False
调用：
if __name__ == '__main__':
s1 = '''''<?xml version="1.0" encoding="UTF-8"?> \
<employees> \
<employee id = '1'> \
<name>linux</name>\
<age>30</age>\
</employee>\
<employee id = '2'> \
<name>windows</name>\
<age>20</age>\
</employee>\
</employees>'''
s2 = '''''<?xml version="1.0" encoding="UTF-8"?> \
<employees> \
<employee id = '3'> \
<name>windows</name>\
<age>20</age>\
</employee>\
<employee id = '4'> \
<name>linux</name>\
<age>30</age>\
</employee>\
</employees>'''
lroot = ElementTree.fromstring(s1)
rroot = ElementTree.fromstring(s2)
compare_xml(lroot, rroot)
希望本文所述对大家的Python程序设计有所帮助。
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