Python 爬取电影网站的信息【如有重复请管理删帖】

本文来源吾爱破解论坛

没有注意论坛有没有相关的帖子，暂吾爱资讯太多了，内容丰富，生怕有重复的，如果重复了，请管理删帖。

自学Python一段时间了，写的代码比较紊乱，也不多，大佬勿喷。


[Python] 纯文本查看 复制代码

#!/usr/bin/env python
# -*- coding: utf-8 -*-
# [url=home.php?mod=space&uid=686237]@date[/url]    : 2018-07-30 17:14:11
# [url=home.php?mod=space&uid=686208]@AuThor[/url]  : --Eruy-- ([url=mailto:yl8923@qq.com]yl8923@qq.com[/url])
# @Version : $Id$
#请求库
import requests

#解析库 bs4  css pyquery json xpath re
from lxml import etree

#        类
class MiNiMp4(object):

        """docstring for GetMovies"""
        
        def GetMovies(self, page):
                url = 'http://www.minimp4.com/movie/?page={}'.format(page)
                html = requests.get(url)                

                htmll = etree.HTML(html.text)        #初始化xml
                hrefs = htmll.xpath('//div[@class="meta"]/h1/a/@href')

                # print(hrefs)
                for url in hrefs:
                        html = requests.get(url)

                        dat = etree.HTML(html.text)
                        movieName = dat.xpath('//div[@class="movie-meta"]/h1/text()')
                        print(movieName)

                        self.saveMovies(movieName)
                # return url
                # 
        @staticmethod
        def saveMovies(data):
                with open('movies.txt','a',encoding='utf-8') as fp:
                        fp.write(data[0]+'\n')




if __name__ == "__main__":
        minimp4 = MiNiMp4()

        for n in range(10):
                minimp4.GetMovies(n)